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unienv_interface.space.spaces.tuple

Implementation of a space that represents the cartesian product of other spaces.

TupleSpace

TupleSpace(backend: ComputeBackend[Any, BDeviceType, BDtypeType, BRNGType], spaces: Iterable[Space[Any, BDeviceType, BDtypeType, BRNGType]], device: Optional[BDeviceType] = None, metadata: Optional[Mapping[str, Any]] = None)

Bases: Space[Tuple[Any, ...], BDeviceType, BDtypeType, BRNGType]

spaces instance-attribute

spaces: Tuple[Space[Any, BDeviceType, BDtypeType, BRNGType], ...] = tuple(new_spaces)

device property

device: Optional[_SpaceBDeviceT]

metadata property

metadata: SpaceMetadata

Read-only description of the data (see "Metadata" in the class docstring); empty if none was given.

shape property

shape: tuple[int, ...] | None

Return the shape of the space as an immutable property.

to

to(backend=None, device=None)

sample

sample(rng: BRNGType) -> Tuple[BRNGType, Tuple[Any, ...]]

create_empty

create_empty() -> Tuple[Any, ...]

Create an empty data structure for this space.

is_bounded

is_bounded(manner='both')

contains

contains(x: Tuple[Any, ...]) -> bool

clip

clip(x: Tuple[Any, ...]) -> Tuple[Any, ...]

Clip every element of x with the subspace at the same index (see Space.clip).

Raises ValueError if x is not a tuple with one element per subspace.

get_repr

get_repr(abbreviate=False, include_backend=True, include_device=True, include_dtype=True)

is_subspaceeq

is_subspaceeq(other: Any) -> bool

Return whether this tuple space is a non-strict subspace of other (⊆).

True iff other is a TupleSpace on the same backend, the two have the same arity, and for every index i the child self.spaces[i].is_subspaceeq(other.spaces[i]) holds recursively. device is ignored.

data_to

data_to(data, backend=None, device=None)

with_metadata

with_metadata(metadata: Optional[Mapping[str, Any]] = None, /, *, replace: bool = False, **updates: Any) -> Space[SpaceDataT, _SpaceBDeviceT, _SpaceBDTypeT, _SpaceBDRNGT]

Return a copy of this space with updated metadata (this space is left unchanged).

metadata and updates are merged into the current metadata, or replace it entirely with replace=True (space.with_metadata(replace=True) clears it). Nested spaces are shared with this space, not copied.

is_subspace

is_subspace(other: Space) -> bool

Return whether this space is a STRICT subspace of other (self ⊂ other).

Defined uniformly for all spaces as::

self.is_subspace(other)  ⟺  self.is_subspaceeq(other) and not other.is_subspaceeq(self)

I.e. self ⊆ other holds but other ⊆ self does not, so self is a PROPER (strict) subspace of other. This is the ⊂ relation versus the non-strict ⊆ provided by :meth:is_subspaceeq.

This definition is used instead of relying on __eq__ because some space classes only have identity __eq__; defining strict containment via the symmetric non-strict check works uniformly for all classes regardless of their __eq__ implementation.

For structurally-distinct-but-mutually-containing spaces (which should not occur under the strict dtype/shape policies enforced by the per-class is_subspaceeq implementations) this degrades gracefully to False: if both self.is_subspaceeq(other) and other.is_subspaceeq(self) hold, the two spaces are considered equivalent and neither is a STRICT subspace of the other.

If either side's is_subspaceeq is not implemented (the base :meth:is_subspaceeq raises NotImplementedError), the exception propagates to the caller — it is NOT swallowed into False so that callers can tell that the comparison is unsupported.

Note: controller-required-space checks should typically use :meth:is_subspaceeq (a controller's required space may exactly equal the env space, in which case the strict is_subspace would return False).

abbr_device staticmethod

abbr_device(spaces: Iterable[Space[Any, _SpaceBDeviceT, _SpaceBDTypeT, _SpaceBDRNGT]]) -> Optional[_SpaceBDeviceT]

Return the shared device across spaces, or None if mixed/empty.